by neilmidlane » Thu Apr 05, 2012 3:55 am
Hi Murray
Thanks for the response, maybe I didn't explain myself clearly enough. An example of the calibration of this methodology can be found in Ferreira, S.M. & Funston, P.J., 2010. Estimating lion population variables: prey and disease effects in Kruger National Park, South Africa. Wildlife Research, 37(3), p.194-206. The method involves using 2 vehicles, one with the lions and a second one a known distance away. The second vehicle plays a recording to attract the lions, moving closer until a response by the lions is noted by the first vehicle. The distance of the response is measured, and the number of lions arriving at the second vehicle, as a percentage of the group size, is also recorded.
Here is a brief excerpt from the paper explaining the results of the calibration:
"We could only estimate a response for lion groups without cubs – the response decayed with distance. The fitted inverse sigmoid model predicted that lions responded up to 4.3 ± 0.9 km (mean ± SD; 95% CI: 2.5-6.1 km) away from call-up stations (Fig. 2a). This means that call-up stations sampled 57.7 ± 24.9 km2 (mean ± SD; 95% CI: 8.9-106.6 km2). We assumed that the area sampled by a call-up was the same for groups with cubs than that for groups without cubs. Approximately 73% of the 28 lion groups without cubs within the sampling area responded to a call-up (0.734 ± 0.076, mean ± SE)."
Given this, I can't understand why it wouldn't be appropriate to state that "there is a 73% (0.734 ± 0.076, mean ± SE) probability of detecting a lion within an area of 57.7 ± 24.9 km2 (mean ± SD; 95% CI: 8.9-106.6 km2) surrounding a call-up station. Following that, the p(detection) in the cell would be a function of the circle's area as a proportion of the cell's area.
I'm not sure if the above gives any more clarity and perhaps changes your opinion at all? Your advice/comments would be welcomed.
Thanks
Neil