It seems that doing it that way forces the proportion of unknowns to be 50% male. Why not use the Huggins/mixture model and let MARK estimate the proportion of males in the unknown group. You could enter the data as 3 groups (M, F, U) and set the two rows of pims for p equal for M and F, and the first row for U = the pim value for p for M, and the 2nd row for U= the pim value for p for F. Fix pi for M and F to any value (since p1=p2). Here's how the MARK input file might look:
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proc estimate link=Sin varest=2ndPart ; model={pi(),p(g)}2};
fixed=1; parm(1)=.314159;
group=1 pi rows=1 cols=1 Square Constant=1;
group=2 pi rows=1 cols=1 Square Constant=1;
group=3 pi rows=1 cols=1 Square Constant=2;
group=1 p rows=2 cols=1 Square Constant=3;
group=2 p rows=2 cols=1 Square Constant=4;
group=3 p rows=2 cols=1 Square; 3; 4;
design matrix constraints=4 covariates=4 identity;
So, we've fixed parameter #1 (pi for M and pi for F = .314159). We're estimating parameter #2 (pi for Unknowns), parameter 3 (p for Males), parameter #4 (p for Females). The 2 heterogeneous groups for Unknown use the M and F p parameters (3 and 4).
My only concern is that I suspect that you don't have recaptures in the unknown group, since it seems unlikely that the same individual would hide his/her rear end from the camera on multiple visits.
Jim